-260=-x^2+7x

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Solution for -260=-x^2+7x equation:



-260=-x^2+7x
We move all terms to the left:
-260-(-x^2+7x)=0
We get rid of parentheses
x^2-7x-260=0
a = 1; b = -7; c = -260;
Δ = b2-4ac
Δ = -72-4·1·(-260)
Δ = 1089
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1089}=33$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-7)-33}{2*1}=\frac{-26}{2} =-13 $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-7)+33}{2*1}=\frac{40}{2} =20 $

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